of the root of quadratic polynomial 2x² –3x+p is 3 find other root also find value of p
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Answered by
2
2 ×3×3 - 3 ×3 + p= o
18- 9+p=o
9+p=0
P=-9
18- 9+p=o
9+p=0
P=-9
Answered by
5
First of all you put the root of the equation then 2 *3² - 3*3 + p= 0
18 - 9 + p=0 then
P = -9
Ond other root are 2x²-3x- 9= 0
(put the value of p in equation)
2x²-6x+3x-9=0
2x(x-3)+3(x-3)=0
(2x+3) (x-3)=0
Hence other root are x= - 3/2,3
18 - 9 + p=0 then
P = -9
Ond other root are 2x²-3x- 9= 0
(put the value of p in equation)
2x²-6x+3x-9=0
2x(x-3)+3(x-3)=0
(2x+3) (x-3)=0
Hence other root are x= - 3/2,3
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