Question

of the three angle of a triangle, one is twice the smallest and another one is thrice the smallest find the angle?​

Answer 1

hi mate here is your answer.,

assume 3 angles of triangle as

smallest angle as=x

second angle =2x

third angle as =3x

USING ANGLE SUM PROPERTY

x+2x+3x=180

6x=180

x=180÷6=30 =x

2x =30×2=60

3x=30×3 =90

hope it helps you

Answer 2

☯️ Given :-

• There are three angles in a triangle
• One is twice the smallest angle
• Other is thrice the smallest angle

☯️R.T.P :-

To find the angles of the triangle ....

☯️Solution :-

let the smallest angle be ' x '

According to Question ,

one side is 2x

Other side is 3x..

We know that,

Sum of all angles in a triangle is 180°

By adding all the angles , we get..

$3x + 2x + x = 180$

$6x = 180$

$x = \frac{180}{6}$

therefore x = 30°

• Smallest angle = 30°
• One angle = 2(30°) = 60°
• Other angle = 3(30°) = 90°

☯️ Verification :

Sum of angles = 180°

So,

$30 + 60 + 90 = 180$

$90 + 90 = 180$

$180 = 180$

Hence verified..........✔️