Question

of the three angle of a triangle ,the second one is one-third of the firstand third angle is 26 degree more than the first angle.find all the three angle of the triangle.

Answer 1

Let the first angle be x °
Second angle = (1/3)x °
Third angle = 26 + x

x+(1/3)x+26+x = 180
2x+(1/3)x = 154
7x = 154×3
x = 66

Hence the angles of the triangle are
1. x = 66°
2. (1/3)66 = 22°
3. x+26 = 26+66 = 92°

Answer 2

let the 1st angle be x degree
therefore 2nd angle =(1/3)x=x/3
3rd angle =x+26 degree
since sum of all the angles of a triangle is 180degree
then, x+(x/3)+(x+26)=180
3x+x+3x+78/3=180
7x+78=540
7x=540-78
7x=462
x=66
1st angle=66 degree
2nd=66/3=22degree
3rd=66+26=92degree