Of the three angles of a triangle are equal and the third angle is greater than each of them by18° find the angles
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Let angles be a, b, c
Given that, a=b
And, c=a+18
We know that by angle sum property
Sum of All Angles of a triangle is 180
a+b+c=180
a+a+a+18=180
3a=180-18
3a=162
a=162/3
a=54
a=b=54
c=a+18
=54+18
=72
Let angles be a, b, c
Given that, a=b
And, c=a+18
We know that by angle sum property
Sum of All Angles of a triangle is 180
a+b+c=180
a+a+a+18=180
3a=180-18
3a=162
a=162/3
a=54
a=b=54
c=a+18
=54+18
=72
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