Of the three angles of a triangle, the second one is one third of the first and the third angle is 26 degrees more than the first angle. Find all the three angles of the triangle.
Answers
Answer:
1angle= 66°
2 angle= 22°
3 angle=92°
Step-by-step explanation:
1 angle= x
2 angle=1/3x
3 angle = 26+x
using angle sum property,
x+1/3x+26+x=180
2x+1/3x+26=180
7x/3+26=180
7x/3=180-26
7x/3=154
7x=462
x=462/7
x=66
1angle= x= 66°
2 angle=1/3x=1/3×66=22°
3angle=26+x= 26+66=92°
• Of the three angles of a triangle, the second one is one third of the first and the third angle is 26° more than the first angle.
• Three angles of the given triangle.
The 1st angle, 2nd angle and 3rd angle of the triangle be x°, y° and z° respectively.
Given that,
The second angle is 1/3 of the 1st angle.
Therefore,
⟶ y° = (1/3) × x
⟶ y° = x/3 ......................(eq(1)
Again, it’s given that
The 3rd angle is 26° more than the 1st angle.
z° = x + 26°.................eq(2)
According to the question :-
x ° + y° + z° = 180°........eq(4)
As we know that,
(The sum of 3 angles of a triangle is 180°)
Now, put y° = x/3 and z° = x + 26° in eq(4)
⟶ x° + (x/3) + (x +26°) = 180°
⟶ 2x° + (x/3) = 180° - 26°
⟶ 7x /3 = 154
⟶ x = 66°
Therefore,
1st angle will be = 66°
2nd angle will be = 66/3 = 22°
3rd angle will be = 66° + 26° = 92°