Find the square root of 3.8 correct to two decimal places
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We have to find the square root of 3.8 correct to two decimal places.
solution : let x = 3.8
= 4 - 0.2
= 4(1 - 0.2/4)
= 4(1 - 0.1/2)
= 4(1 - 1/20)
now taking square root of x,
x½ = [4(1 - 1/20)]½
= (4)½ [1 - 1/20]½
= 2 [1 - 1/20]½
from binomial expansion, if y = (1 - x)ⁿ, where x << 1
then, y ≈ 1 - nx
in above expression we see, 1 >> 1/20
so, [1 - 1/20]½ ≈ 1 - 1/40 = 39/40 = 0.975
now x½ = 2 × 0.975 = 1.95
Therefore the square root of 3.8 correct to two decimal places is 1.95
[note : if you want to get more accurate value just use expansion of (1 - x)ⁿ = 1 - nx + n(n - 1)/2! x² - n(n - 1)(n - 2)/3! x³ + .... ]
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