Question

Of the three numbers, second is twice the first and is also thrice the third, if the average of the three numbers is 44. find the largest number?

Answer 1

Let the numbers be X,Y and Z
    Y= 2X = 3Z
From the above relation we can find the ratio X:Y:Z = 3:6:2
                                      3k+6k+2k=11k
                                 11k = 44
                                   3
                                 k = 12
therefore, the largest number = 12 * 6 = 72