Question

Of the three numbers, the first is twice the second and is half of the third. if the average of three numbers is 56, then the smallest number is

Answer 1

let the first number be x, second number be y and third be z
      x= 2y = z/2
    from the above relation we can find the ratio of x:y:z = 2:1:4
    therefore the numbers are 2k,1k and 4k
                              7 k = 56
                               3
                               k = 24, which is the smallest number.