Of the three numbers the first is twice the second and half of the third.if the average of three numbers is 56..difference between first and third number is.
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let 2nd no be x
1st be 2x
3rd be 4x
a/q
x + 2x + 4x /3=56
7x= 56×3
x = 56×3/7=24
diff b/w 1st nd 3rd= 4x - 2x =2x
nd 2x = 2×24=48
1st be 2x
3rd be 4x
a/q
x + 2x + 4x /3=56
7x= 56×3
x = 56×3/7=24
diff b/w 1st nd 3rd= 4x - 2x =2x
nd 2x = 2×24=48
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