Question

Of the three numbers, the first is twice the second
and is half the third. If the average of three numbers
is 58, the three numbers in order are​

Answer 1

Step-by-step explanation:

Let the second no. be x

then the first no. will be 2x

since 1st one is half the third,

I.e, 3rd no. is twice the 1st, then the third no. is 4x

avg. =

$x + 2 x + 4x \div (3) = 58$

$7x = 58 \times 3$

$x = 58 \times 3 \div (7)$

$= 174 \div 7$

$24 \frac{6}{7}$