Of the three numbers whose average is 60, the first is one-fourth of the sum of the others
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Let the no be x , y , z
Given ,
Avg of three no = 60
I.e ( x+y+z )/3 = 60
Also , x = (y+z)/4
4x = y +z
Put these in 1st eqn
X +4x = 60*3
5x = 180
X = 36
Given ,
Avg of three no = 60
I.e ( x+y+z )/3 = 60
Also , x = (y+z)/4
4x = y +z
Put these in 1st eqn
X +4x = 60*3
5x = 180
X = 36
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