Of the two supplementary angle the measure of the large angle is 50 degree more than the measure of the smaller angle find the measure of each angle 0
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let one angle is x°
therefore, other angle is 50 more than first,i.e.,
other angle= (x+50)°
A.T.Q.
x+x+50= 180°
2x+50= 180°
2x=180-50=130°
x=130/2=65°
therefore, one angle=x=65°&
other angle=x+50=65+50=115°
therefore, other angle is 50 more than first,i.e.,
other angle= (x+50)°
A.T.Q.
x+x+50= 180°
2x+50= 180°
2x=180-50=130°
x=130/2=65°
therefore, one angle=x=65°&
other angle=x+50=65+50=115°
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