Question

The diagonals of a parallelogram ABCD intersect atO.If angle BOC=90°and angle BDC=50°then angle OAB=?

Answer 1

Answer:

Step-by-step explanation:

angle BOC = angle ABO      (alternate angles)   equation 1

angle BOC + angle AOB = 180 ( Linear pair)

90+angle AOB=180

angle AOB = 90     equation 2

In TRIANGLE AOB

angle ABO+ angle AOB + angle OAB = 180    (angle sum property)

40+90+angle OAB= 180       (from equation 1 and 2)

angle OAB= 180- 130

angle OAB = 50.

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