Question

of three consecutive odd integers, k is the middle one.if the difference between the products of the last 2 and first 2 is 28,find the three integers

Answer 1

Answer:

k = -14

Three integers : -13 , -14 , -15

Step-by-step explanation:

Let three terms be : (k+1) , k , (k-1)

Then ,

Then , According to question ,

Then , According to question , (k-1)k - k(k+1) = 28

Then , According to question , (k-1)k - k(k+1) = 28 k² - k -(k² + k) = 28

Then , According to question , (k-1)k - k(k+1) = 28 k² - k -(k² + k) = 28 k² - k - k² - k = 28

Then , According to question , (k-1)k - k(k+1) = 28 k² - k -(k² + k) = 28 k² - k - k² - k = 28 -2k = 28

Then , According to question , (k-1)k - k(k+1) = 28 k² - k -(k² + k) = 28 k² - k - k² - k = 28 -2k = 28 k = -14

Then , According to question , (k-1)k - k(k+1) = 28 k² - k -(k² + k) = 28 k² - k - k² - k = 28 -2k = 28 k = -14 Hence the three integers will be :

Then , According to question , (k-1)k - k(k+1) = 28 k² - k -(k² + k) = 28 k² - k - k² - k = 28 -2k = 28 k = -14 Hence the three integers will be : (k+1) = -14 + 1 = -13

Then , According to question , (k-1)k - k(k+1) = 28 k² - k -(k² + k) = 28 k² - k - k² - k = 28 -2k = 28 k = -14 Hence the three integers will be : (k+1) = -14 + 1 = -13 k = -14

Then , According to question , (k-1)k - k(k+1) = 28 k² - k -(k² + k) = 28 k² - k - k² - k = 28 -2k = 28 k = -14 Hence the three integers will be : (k+1) = -14 + 1 = -13 k = -14 (k-1) = -14-1 = - 15