Question

of three positive number the product of first and second is 24 second and third is48 and that of first and third is 32 let find the three numbers​

Answer 1

Answer:

The three numbers are 4, 6 and 8

Step-by-step explanation:

Let the numbers be a , b , c

a * b = 24     ⇒ a = 24/b

b * c = 48     ⇒ b = 48/c

c * a = 32     ⇒ a = 32/c

24/b = 32/c

24 c = 32 b

3 c   = 4 b

3 c    = 4 * 48/c

c²    =  4 * 16

c      =   2 * 4 = 8

∴a = 32/c = 32/8 = 4

∴b = 48/c = 48/8 = 6

Answer 2

Answer:

a= 4, b=6, c=8

Step-by-step explanation:

Let the numbers be a, b, c

ATQ

ab=24

bc=48

ac=32

b=24/a —(I)

Substituting (I) in bc= 48

24c/a = 48

c/a = 2

c = 2a — (II)

Substituting (II) in ac=32

2a² = 32

a² = 16

a=+4 or -4

But it cannot be -4 because numbers are positive

.•. a=4

c=2a

c= 8

b= 24/a

b= 6