Question

of triangle
find the area of triangel
the points
(8,-5).(-2,-2) and (5,0)
formed by​

Answer 1

Answer:

where is the picture

Step-by-step explanation:

Answer 2

Given

of triangle find the area of triangle the points (8,-5).(-2,-2) and (5,0) formed by​

Answer

To calculate the area of the triangle whose vertices are (0,16),(0,5) and(8,2).

We know that if (x,y1), (x2,y2) and (x3,y3) are the vertices of the triangle, then the area of the triangle is given by:

Area of the triangle = (1/2) |{(x2-x1)(y2+y1) +(x3-x2)(y3+y1)+(x1-x3)(y1+y2)}|

Therefore the area of the triangle whose vertices are (0,16), (0,5), (8 ,2) is given by:

Area of the triangle = (1/2) {(0-0)(16+5) +(8-0)((2+5) +(0-8)(2+16)}

Area of triangle = (1/2) |{0 + 56 - 144}|

Area of the given triangle = (1/2) * 88 = 44 sq units.

W can calculate the area by Heron's formula also:

Area of the triangle = sqrt{s(s-a)(s-b)(s-c)}, a, b ,c are sides of triangle, s = (a+b+c)/2.

a = sqrt(0+(16-5)^2 )= 11

b = sqrt[8^2+ (2-14)^2] = sqrt260 = 16.125..

c =sqrt[(8-0)*2+(2-5)^2] = sqrt73 = 8.544..

Therefore s = (11+sqrt260+sqrt73)/2 = 17.834..

Area of the triangle = sqrt{(17.834..)(6.834...)(1.7097..)(9.2902...)}

Area of the triangle = sqrt1935.999998

Area of the triangle = 43.999...sq units

#Good morning

#Angry prash

#Angry amry