Question

Of two oxides of iron,the first contain 22%and second contain 30% of oxygen by weight.the ratio of weight of iron in the two oxides that combine with same weight of oxygen is

Answer 1

Hey Dear,

◆ Answer -

3 : 2

● Explanation -

Let's take 100 g of both oxides.

In first oxide -

Oxygen = 100 × 22/100 = 22 g

Iron = 100 - 22 = 78 g

Iron/oxygen = 78/22

In second oxide -

Oxygen = 100 × 30/100 = 30 g

Iron = 100 - 30 = 70 g

Iron/oxygen = 70/30

Therefore, ratio of weight of iron that combines with same mass of oxygen will be (78/22) / (70/30) = 3 : 2.

Thanks dear...