Question

ogether,two pipes can fill a reservoir in 3/4 of an hour.Pipe1 needs one hour ten minutes(1 1/6 hours)to fill the reservoir by itself.How long would pipe 2 need to fill the reservoir by itself?

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

2 hours 6 mins

Step-by-step explanation:

Flow with pipe 1= x, in one hour fills 1/x of tank

Flow with pipe 2= y, in one hour fills 1/y of tank

Two pipes together fill up reservoir part in an hour:

• 1/x+1/y in one hour, so

• 1/x+1/y= 1/3/4= 4/3

Pipe 1 will fill the reservoir part in one hour:

• 1/x= 1/ 1 1/6= 1/ 7/6= 6/7

Pipe 2 will fill the reservoir part in one hour:

• 1/y= 4/3-6/7= 10/21

Time for pipe 2 to fill the reservoir:

• y= 21/10= 2 1/10 hours= 2 hours 6 mins