Question

ok ok travelling do not at 50 km per hour plans west and travel at the same speed what is the change in velocity

Answer 1

Hey dear,

● Answer -
∆v = 14.64 km/hr

● Explaination -
[Refer to the figure for better understanding]

Let t same time for which truck travels towards north and towards west.

Distance towards north, AB = vt = 50t
Distance towards west, BC = vt = 50t

Total displacement is given by -
AC = √(AB^2 + BC^2)
AC = √(50t^2 + 50t^2)
AC = 50√2t

Resultant velocity -
v = total distance / total time
v = 50√2t / 2t
v = 50/√2 km/hr

Change in velocity is calculated by -
∆v = 50 - 50/√2
∆v = 14.64 km/hr

Therefore, change in velocity is 14.64 km/hr.


Hope this helpz you...

Answer 2

"Truck travels north (OA) at $v_{1}$ = 50  km /hr

Truck travels west (AB) at $v_{2}$ = 50  km /hr

Let the truck travel for a time t in both the directions.

Thus, the distance OA = 50t       (Since, Distance = Speed × Time)

The distance AB = 50t

We know that,

    Velocity = $\frac{Displacement }{Time}$

   Displacement OB $= \sqrt { (OA)^{ 2 }+(AB)^{ 2 } } =\sqrt { (50t)^{ 2 }+(50t)^{ 2 } } =50t\sqrt { 2 }$

  Total time = 2t

Therefore, Velocity $= \frac{50t\sqrt { 2 }}{2t} = 25\sqrt{2}$

                Velocity = 35.355 km/hr

Change in velocity $\Delta v = 50 - 35.355 =14.645 km/hr$"