Okay the question is the one with the circle answer fast
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Here, ∠DAC=∠DBC=55
o
...(angles in the same segment).
Then, ∠DAB=∠DAC+∠CAB=55
o
+45
o
=100
o
.
Now, ∠DAB+∠DCB=180
o
...(opposite angles of cyclic quadrilateral ABCD)
⇒∠DCB=180
o
−100
o
=80
o
.
Please mark me as Brainlyest Please its at last point to go to experts so if want conform me see the given below image
o
...(angles in the same segment).
Then, ∠DAB=∠DAC+∠CAB=55
o
+45
o
=100
o
.
Now, ∠DAB+∠DCB=180
o
...(opposite angles of cyclic quadrilateral ABCD)
⇒∠DCB=180
o
−100
o
=80
o
.
Please mark me as Brainlyest Please its at last point to go to experts so if want conform me see the given below image
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