Question

om: Multiply both sides of the equation by 2. We get
ve su acted from both sides of the equation, not a number (const
ing the variable. We can do this as variables are also numbers. Ale
angre both sides amounts to transposingxto LHS.
22=2+5
20-1=x+5-* (subtracting from
x=5
7 3
-=-*-14
2 2.
ple 13: Solve 5x +
3
(57) = 2x(3 x - 14



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Answer 1

Step-by-step explanation:

Let us take an equation x+2y=5 .....(1)

Put x=1 in eqn (1)

⇒y=2

So,x=1,y=2 is a solution of the equation

Multiplying both sides of equation 1() by 3, we get

3x+6y=15

Put x=1,y=2 in LHS

LHS =3×1+6×2=15= RHS

Hence, on multiplying an equation by a non-zero number , the solution remains same.

Let us divide both sides of equation (1) by 2

⇒ 2x+y=

2

5

Put x=1,y=2 in above equation

LHS =

2

1

+2=

2

5

= RHS

Hence, on dividing or multiplying an equation by a non-zero number, the solution remains the same.

Answer 2

Answer:

Above answer is right ok bye