Question

Om walks 8m west and 15 m north to reach the opposite corner of rectangular field shiv walked from the same point diagonally to the opposite,corner what is the distance walked by Shiv

Answer 1

Hey mate ,nice question.

Here 8m and 15 m are the breadth and length of the rectangle respectively.

And diagonal formula is
$d = \sqrt{ {l}^{2} + {b}^{2} }$
So
$d = \sqrt{ {8}^{2} + {15}^{2} }$
Thus d= underroot 289

d=17m...

Hope it helps❤️❤️❤️

Answer 2

AC =√225 +64
AC=√289
AC=17 meter
Therefore distance covered by shiv =AC =17 M