on 1 st jan 2016, rodhey to save Rs.20, Rs.25 on the second day and Rs.30 on the third day . he decides to save like this . what would his total saving at end of the month March ?
please give step by step explanation
I will make as breainlieast
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Answered by
1
Answer:
74115 ₹
Step-by-step explanation:
on first day rodhey saved = ₹20
on second day he saved=₹25
on third day he saved = ₹30
his total savings = (20+25+30+till march)
here,
d= 1
a= 20
n= 366( as 2016 is a leap year)
Now,
Sn = n/2 [2a+(n-1) d]
S366 = 366/2 [2×20+(366-1)1]
= 183 (40+365)
= 183 × 405
= ₹ 74115
Answered by
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Answer = 74115//
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