Math, asked by pjashan4004, 11 months ago

On 1st january 2016 , sanika decides to save ₹ 10 , ₹ 11 on second day , ₹12 on third day . If she decides to save like this , then on 31 st december 2016 what would be her total saving

Answers

Answered by aryanashokpatil1314
10

Hey dude here is yours ans••••

Step-by-step explanation:

Let her saving at day one be t1=10

And on second day be t2=11

And on third day be t3=12.

# a=10, d= t2 - t1 = 1,tn=31

# tn= a+(n-1)xd

t31= 10+(31-1)x1

= 10+30x1

= 10+30

t31 = 40 .

Therefore,on 31st December 2016 sanika total savings will be RS=40.


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aryanashokpatil1314: Hope dude it is hopefully to you
shreya32457: wrong
shreya32457: u gave the ANs but it is wrong
shreya32457: read the question carefully
yogeshpande59: Wrong
wwwmjurez: Wrong correct is 70,445
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