Question

On 1st January 2020 Subod sold goods to Shaheb for Rs. 30000. Shaheb paid Rs.6000 in

cash and for the balance accepts three bills – No. 1 for Rs. 7000 at one month, No. 2 for

Rs. 8000 at two months and No. 3 for Rs. 9000 at 3 months. .On 16th January Subod

endorse 1st bill to Nahar, his creditor in full settlement of Rs. 7100, discounts the 2nd bill at

his bank for Rs. 7920 and retained the third bill till maturity..All the bills are dishonoured

and Rs. 500 being paid as noting charges.. Give journal entries in the books of subod and

Shaheb.​

Answer 1

Answer:

$\huge{\underline{\sf{\orange{Answer -}}}}$

$let \: the \: whole \: quantity \: = x$

$A/Q$

$5\% \: of \: x = 600 \\ \\ = > \frac{5 \times x}{100} = 600 \\ \\ \\= > 5 \times x = 600 \times 100 \\ \\ \\ \ \: = > x = \frac{600 \times 100}{5} \\ \\ \: \\ = > x = \frac{120 \times 100}{1} \: \\ \\ x = 12000$

Therefore, The whole quantity = 12000

Answer 2

Answer:

Answer−

\begin{gathered}let \: the \: whole \: quantity \: = x \\ \end{gathered}

letthewholequantity=x

A/QA/Q

\begin{gathered}5\% \: of \: x = 600 \\ \\ = > \frac{5 \times x}{100} = 600 \\ \\ \\= > 5 \times x = 600 \times 100 \\ \\ \\ \ \: = > x = \frac{600 \times 100}{5} \\ \\ \: \\ = > x = \frac{120 \times 100}{1} \: \\ \\ x = 12000 \end{gathered}

5%ofx=600

=>

100

5×x

=600

=>5×x=600×100

=>x=

5

600×100

=>x=

1

120×100

x=12000