Question

on 2
In the figure A and B are the mid- points of two equal chords PQ and RS
respectively of a circle with center O. Prove that triangle OAQ is congruent to triangle OBS.​

Answer 1

Answer:

pls see the picture

hope it helps

Answer 2

Answer with Step-by-step explanation:

In given figure,

PQ=RS

A and B are mid-points of PQ and RS.

OA=OB

Because when two chords are equal then their distance from center are equal.

In triangle OAQ and OBS

OA=OB

PQ=RS

$\frac{1}{2}PQ=\frac{1}{2}RS$

$AQ=BS$ (PA=AQ,RB=BS)

$OQ=OS$   (Radius of circle are equal)

$\triangle$OAQ$\cong\triangle$OBS

Reason: SSS postulate

Hence, proved.

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