on a 100 meters track a train travels the first 30 kilometer at a uniform speed of 30km/h. how fast must the train travels the next 70 kilometers so as to average 40km/h for the entire trip.
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Given:
Distance 1 = 30 Km
Distance 2 = 70 Km
Speed = distance /time and
avg speed = total distance / total time taken
when the train acquired a speed of 30km/h, the time taken is -
30 = 30/t .... 30/30
T1 = 1 second
As we know that the avg speed = total distance / total time taken
[ where time 2 = time for the second part, for 70 km ]
40 = 100 / 1 + time 2
40 + 40 time 2 = 100
40time2 = 100 - 40
40time2 = 60
Time2 = 1.5 hours
Speed for the second part is
= distance 2 /time 2
s = 70 / 1.5
s = 46.666.. km/h or 46.7km/h (approx)
Therefore, train has to travel with speed of
46.7 k. / h
Distance 1 = 30 Km
Distance 2 = 70 Km
Speed = distance /time and
avg speed = total distance / total time taken
when the train acquired a speed of 30km/h, the time taken is -
30 = 30/t .... 30/30
T1 = 1 second
As we know that the avg speed = total distance / total time taken
[ where time 2 = time for the second part, for 70 km ]
40 = 100 / 1 + time 2
40 + 40 time 2 = 100
40time2 = 100 - 40
40time2 = 60
Time2 = 1.5 hours
Speed for the second part is
= distance 2 /time 2
s = 70 / 1.5
s = 46.666.. km/h or 46.7km/h (approx)
Therefore, train has to travel with speed of
46.7 k. / h
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