Question

on a 4kg mass, 5 Newton of force acts for 0.2 sec. the impulse imparted to the mass is (in kg m/s)​

Answer 1

Answer:

It is given that,

Mass of the object, m = 3 kg

Force acting on the object, F = 5 N

Time of contact, t = 0.1 s

Let J is the impulse imparted to mass. It is equal to the product of force and time of contact. It is given by :

J=F\times tJ=F×t

J=5\ N\times 0.1\ sJ=5 N×0.1 s

J = 0.5 kg-m/s

So, the impulse imparted to the mass is 0.5 kg-m/s. Hence, this is the required solution.

Answer 2

Explanation:

F=5N ; t=0.2 sec or 15 sec.

Impulse=Force × time.

Impulse=5×1/5

=1.

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