On a 60 km stretch of road, a cyclist travels first 20 km at a uniform speed of 20 km/hr. how fast must he travel the remaining distance so that his average speed is 10 km/hr for the entire trip.
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Step-by-step explanation:
Given:
- Total distance =60km
- Average speed of entire journey=20km/h
- Total Time taken = total distance/average
- speed =60/10 =6hr
Case :1
Let us CALCULATE
time taken to cover first 20km
Speed=20km/h
Distance=20km
T=distance/ speed=20/20 =1hr -equation ( 1)
Case: 2
Let speed be =Xkm/h
X=40 KM/t t=40/X hours ----equation( 2)
Total time = add equation 1 and 2
=1 +40/X
Since total time =3 h
6 =1 +40/X
6-1 =40/X
5 =40/X
X=8 km/h
Therefore cyclist should travel next 40 km distance at a speed of 8 km/h.
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