Math, asked by shiva9142, 1 month ago

rationalise the denominator 1/✓2-✓3​

Answers

Answered by Goofdood
3

Answer:

Here is your answer.

Hope it helps

Attachments:
Answered by Salmonpanna2022
5

Answer:

 \sqrt{2}  +  \sqrt{3}  \\

Step-by-step explanation:

 \frac{1}{ \sqrt{2} -   \sqrt{3} }  \\

In 1/√2-√3 , the denomination is √3-√3. Multiplying the. Numerator and denomination by √2+√3, we get

 \:   \longrightarrow \:  \frac{1}{ \sqrt{2}  -  \sqrt{3} }  \times  \frac{ \sqrt{2} +  \sqrt{3}  }{ \sqrt{2} +  \sqrt{3}  }  \\

 \:   \longrightarrow \:  \frac{ \sqrt{2} +  \sqrt{3}  }{ ( \sqrt{2} {)}^{2}   + ( \sqrt{3} ) ^{2}  }  \\

 \:   \longrightarrow \:  \frac{ \sqrt{2} +  \sqrt{3}  }{2 - 3}  \\

 \:   \longrightarrow \:  \frac{ \sqrt{2}  +  \sqrt{3} }{1}  \\

 \:   \longrightarrow \:  \sqrt{2}   +  \sqrt{3}  \:  \:  \: Ans.

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