On a 60 km track, a train travels the first 20 km with uniform of 30 km.hr⁻¹. How fast must the train travel to the next 40 km so as its average speed will be 40 km.hr⁻¹ for the entire trip.
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Answer:
Let the speed of the train for next 30 km be "x".
Since, t=
s
d
So, time taken by the train for first 30 km,
t
1
=
30km/h
30km
=1h
Time taken by the train to travel next 30 km:
t
2
=
xkm/h
30km
=(30/x)h
Time taken for the entire trip:
t=
4km/h
60km
=1.5h
So, 1+
x
30
=1.5
⇒x=60km/h
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