on a 60km straight road , a bus travel the first 30km with a uniform speed of 30km/h . how fast must the bus travel the next 30 km so as to have average speed of 40km/h for the entire trip ?
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Hey.
Here is the answer.
Total distance = 60 km
distance travelled with 30kmph is 30 km
so, time taken = 30/30 = 1 h
Let he cover the rest 30 km with a speed of x kmph
So, time taken = 30/x h
As, total distance = 60 km
total time = 1 + 30/x
so, average speed = 60/(1 + 30/x)
or, 40 = 60x/(x+30)
or, 40x + 1200 = 60x
or, 20x = 1200
so, x = 60 kmph
Thanks .
Here is the answer.
Total distance = 60 km
distance travelled with 30kmph is 30 km
so, time taken = 30/30 = 1 h
Let he cover the rest 30 km with a speed of x kmph
So, time taken = 30/x h
As, total distance = 60 km
total time = 1 + 30/x
so, average speed = 60/(1 + 30/x)
or, 40 = 60x/(x+30)
or, 40x + 1200 = 60x
or, 20x = 1200
so, x = 60 kmph
Thanks .
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