Question

on a bulb 60w and 120v are drawn. how much is its resistance​

Answer 1

Answer:

Please see the attachment....

Answer 2

$\huge{\bold{Solution :- }}$

Given

$P = 60w \: \: V \: = 120v \\ \\ power \: is \: given \: as \\ \\ p = \frac{ {v}^{2} }{r} \\ \\ r = \frac{ {v}^{2} }{p} \\ \\ = \frac{ {120}^{2} }{60} \\ \\ = \frac{120 \times 120}{60} \\ \\ = 240 \\ \\ Hence, \: the \: resitence \: of \: the \: bulb \: is \: 240 \: ohm$