Question

on a bulb it is written as 220vand 40w.then the amount of electric current flows through the bulb and resistance will be A)2/11 A and 1210 B)11/2A and 1210 C)2/11Aand 1/1210 D)2Aand 1210​

Answer 1

we know that P=V²/R

so,

:)40=220 × 220 / R

:)220 × 220/40= R

:)R=1210 ohm

Now,

I=V/R

=220/1210

=20/110

=2/11 A

hope it's correct

. .