Question

on a circular cycle lane whose inner radius is 50m and outer radius 71m, soil preparation is to be done at the cost of 2per m square . find the expenditure incurred.​

Answer 1

Answer:

Area of lane = π[(r1)² - (r2)²] = π(71²-50²) = π*(71+50)(71-50) = π*121*21 = 22*121*3 = 7986m²

cost of soil preperation = 7986*2 = 15972 (Ans.)

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Answer 2

expenditure incurred. is Rs. 15972

Step-by-step explanation:

inner radius of the circular lane  r = 50 m

outer radius of the circular lane R = 71 m

area of the lane = $\pi (R^2-r^2)$

= $\frac{22}{7}(71^2-50^2)$

= 7986 m²

given that

the cost of soil preparation  1 m² = 2 Rs.

cost of soil preparation  7986 m² = 2 × 7986 = Rs. 15972

hence , expenditure incurred. is Rs. 15972

#Learn more :

The area of circular pathway is 88 m  square if the radius of outer circle is 8 metre find the radius of inner circle ​

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