on a dry day, the maximum safe speed on which a car can be driven on a curved horizontal road without skkiding is 7m/s .when the road is wet ,the friction force between the tyres and road reduces by 25%.how fast can the car safely take turn on the wet road?
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V is directly proportional to √u
Then
v1²/v2²=u1/u2
49/v2²=100/100-25
49/v2²=4/3
V2²=49×3/4
V2=7√3/4
Then
v1²/v2²=u1/u2
49/v2²=100/100-25
49/v2²=4/3
V2²=49×3/4
V2=7√3/4
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