On a flat ground, two towers of 10 meter and 26 meter height are at a distance of 63 meters from each other ,how far a part will the upper ends of the two towers be ?
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Answer:
30.5 m
Step-by-step explanation:
Height of tower 1 = 10m
Height of tower 2 = 26m
Distance between the 2 towers = 63m
Since a right angled triangle is formed where the hypotenuse ids the distance between the tops, Pythagoras theorum can be used.
Hypotenuse sq. = Sum of sq. of other 2 sides.
H sq = 16 sq + 63 sq
H sq = 256 + 676
H sq = 932
H = under root 932
H = 30.5
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