Question

on a frictionless table a body of 1 kg is made to slip by 2 metres. the work done is​

Answer 1

Answer:

19.6J

Step-by-step explanation:

W.D is eqaul to F*S so F 9.8N and s 2m.

so w.d is eqal to 19.6j

Answer 2

Step-by-step explanation:

Work done = Force × Displacement

Here, Displacement = 2m (given)

And, Force = mass × acceleration

= 1kg (given) × 9.8 m/s^2 (gravitational acceleration)

= 9.8kgm/s^2

= 9.8 N

Work done = Force × Displacement

= 9.8N × 2m

= 19.6 Nm

= 19.6 Joule

The answer given in your book might be 20 Joule depending on gravitational acceleration as some take it as 10 m/s^2 (approx.) No worries because this answer is correct and exact.

Hope it helps :)