on a graph paper, draw the graph of linear equation 3x-2y =4 and x+y-3=0. Also, find their point of intersection on the graph
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Given : 3x - 2y = 4 , x + y - 3 = 0
To find : draw the graph and find the coordinates of the point where the two graph lines intersect
Solution:
3x - 2y = 4
x + y - 3 = 0
put x = ( 3 - y) in 1st
=> 3(3 - y) - 2y = 4
=> 9 - 5y = 4
=> -5y = -5
=> y = 1
=> x = 2
x 3x-2y = 4 x + y - 3 =0
-3 -6.5 6
-2 -5 5
-1 -3.5 4
0 -2 3
1 -0.5 2
2 1 1
3 2.5 0
4 4 -1
( 2, 1) is the intersection points
graph attached
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