On a morning walk , three person step off together and their step measures 90cm, 120cm and 130 cm respectively. Then the minimum distance each should walk so that each can cover the same distance in complete steps ?
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Answer: 360
Step-by-step explanation:
So in order to find the minimum dis tance we must find their LCM
SO the prime fractorisation of this three no .
90=2 ×3²×5
120=2³×3×5
130= 2×5×13
LCM = 2³×3²×5
= 8 ×9×5 =360
Each must walk 360 cm to cover same distance
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