On a morning walk, three persons step off together and their steps measure
40cm, 42cm and 45cm respectively. What is the minimum distance each
should walk so that each can cover the same distance in complete steps. Also
find the number of steps of each person.
Answers
Answer:
To find the minimum distance each should walk to cover the same distance, find the lcm of 40,42 and 45.
The LCM will be 2520.
For the second part of the question, divide 2520 by each:
For 1st person, 2520/40=63
For 2nd person, 2520/42=60
For 3rd person, 2520/45=56
In this problem we have to find the Least Common Multiple also known as the LCM in order to find the minimum required distance and we use LCM to find the minimum distance which is asked in the question.
Finding LCM:
40 = 2 * 2 * 2 * 5
42 = 2 * 7 * 3
45 = 3 * 3 * 5
LCM = 2 * 2 * 2 * 5 * 3 * 3 * 7 = 40 * 63= 2520 cm
Therefore, the minimum distance which each person has to walk or take is 2520 cm to cover the same distance.
The Distance covered by each person individually:
Distance covered by First person = 2520 / 40 = 63 steps
Distance covered by the Second person = 2520 / 42 = 60 steps
Distance covered by the Third person = 2520 / 45 = 56 steps