Question

on a morning walk, three persons step off together and their steps measure 40 cm, 42 cm, amd 45 cm respectively. what is the minimum number of distance each should walk so that each can cover the same distance in complete steps?

Answer 1

Step-by-step explanation:

Since, the three persons start walking together.

Therefore, The minimum distance covered by each of them in complete steps = LCM of the measures of their steps

= LCM (40, 42, 45)

40 = 2 x 2 x 2 x 5 = 23 x 5

42 = 2 x 3 x 7

45 = 3 x 3 x 5 = 32 x 5

=> LCM (40, 42, 45) = 23 x 32 x 5 x 7

= 2520

=> Each person should walk a minimum distance of 2520 cm in complete steps.

Answer 2

Answer:

$hope \: it \: helps \: you$

Step-by-step explanation:

Given,

LCM 40cm,42cm,45cm

Lowest common multiple by

40 => 2 × 2 × 2 × 5 = 2³ × 5

42 = 2 × 3 × 7

45 = 3 × 3 × 5 × 7

=> 840 × 3 = 2520

So the distance to be covered by each = 2520cm