Question

On a morning walk, three persons step off together and their steps measure 90 cm, 120 cm and 130 cm respectively. Then, the minimum distance each should walk so that each can cover the same distance in complete steps

Answer 1

Answer:

for this question we need the LCM of the steps

90,120,130 ÷2

45,60,65 ÷2

45,30,65 ÷2

45,15,65 ÷3

15,3,65 ÷3

3,1,65 ÷3

1,1,65 ÷5

1,1,13 ÷13

1,1,1

LCM =2×2×2×3×3×3×5×13

=14040 cm

=140.4 m

Step-by-step explanation:

Answer 2

Given :  On a morning walk, three persons step off together and their steps measure 90 cm, 120 cm and 130 cm respectively.  

To find : the minimum distance each should walk so that each can cover the same distance in complete steps

Solution :

Let say Distance Covered  = d

Then Step walked  are  d/90    , d/120  & d/130

=> d = 90A   = 120B  = 130C

=> d must be minimum the LCM of 90 , 120 & 130

90 = 2 * 3 * 3 * 5

120 = 2 * 2 * 2 * 3 * 5

130 = 2 * 5 * 13

LCM = 2 * 2 * 2 * 3 * 3 * 5 * 13

= 4680

Hence minimum distance need to Walk = 4680 cm   = 46.8 m

Learn more:

find the lcm of 90 and 120 - Brainly.in

https://brainly.in/question/7842410

Explain step by step ​ - Brainly.in

https://brainly.in/question/13119140