On a newly constructed bridge only cars and bikes can pass and each time a car passes it pays Rs. 10 and a bike pays Rs. 5 for each trip. A total of 250 cars and bikes passed on a certain day and amount collected was Rs. 1750. How many cars and bikes passed on that day?
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Answer:
no of bikes is 150
no of cars is 100
Step-by-step explanation:
let no of bikes=x
no. of cars = y
hence by condition
x+y =250 ____eqn 1
each car pays rs 10 and bike pays rs 5
hence
total collection is 5x + 10y = 1750 ___eqn 2
multiply eqn1 by 5
5x+5y=1250 __eqn3
subtract eqn3 from eqn2
hence value of y = 100
put value of y in eqn 1
x+y=250
x+100=250
hence x = 250-100
x=150
Answered by
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Answer:100cars and 150 bykes
Step-by-step explanation:
100×10=1000
150×5=750
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