Question

On a planet, a body dropped from a height of 8m, reaches the ground in 2 seconds. if the length of a simple pendulum on that planet is 1m, the period of oscillation is

Answer 1

Answer:

T = 3.14 sec

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Explanation:

Case 1:

Given,

Height of the object: 8m

Time taken: 2sec

Initial Velocity: 0m/s

Using s = ut + 1/2at^2

=> 8 = 1/2 x g x 4

=> g = 4m/s^2...........................(1)

Case 2:

Given,

Lenght of the simple pendulum: 1m

We know that Time Period of a Pendulum is given by:

=> T = 2π√(l/g)

=> T = 2π x √(1/4)

=> T = 2π x 1/2

=> T = π sec

=> T = 3.14 sec or 3.14159 sec