Question

On a see-saw, two children of masses 30 kg and 50 kg are sitting on one side of it at distances 2 m and 2.5 meter respectively from the mid point ,where should the man of 80 kg sit to balance the sea saw

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Answer 1

Let the two children be sitting on the left arm. They will produce anti-clockwise moment due to their weights about the middle point.

Total Anti-clockwise moment = 30 kgf x 2m + 50kgf x 2.5 m

= 60 kgf m + 125 kgf m = 185 kgf m

To balance it, the man should sit on the right arm (to produce clockwise moment). Let his distance from the middle be x m. Then

Clockwise moment = 80 kgf x X m = 80x kgf m

By the principle of moments,

Anti-clockwise moment = Clockwise moment

185 = 80x

or x = 185/80m

= 2.3125m(on the other side).

Answer 2

Answer:

2.31256 m

Explanation:

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