On a semicircle with AB as diameter, a point C is taken so that im 2AB:: 0°. Find mZACB nd m/ADe
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Answer:
Since angle in a semi-circle is a right angle.
Therefore, ∠ACB=90
o
In △ABC we, have
∠CAB=30
o
{given } and ∠ACB=90
o
∠ABC+∠CAB+∠ACB=180
0
∴∠ABC=60
o
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