Question

on a single throw of 2 dices, the probability of getting twin numbers is?​

Answer 1

Step-by-step explanation:

the probability of getting twin numbers is 1/6

Answer 2

Answer:

GIVEN :-

• Once throw 2 dice
• Sample space =36

TO FIND :-

Fine the probability of getting twin numbers is?

FORMULAE :-

$P(E) = \frac{Number \: of \: favourable \: outcomes}{Total \: number \: of \: outcomes}$

SOLUTION :-

two dice are thrown we get outcome as

[ (1,1),(1,2),(1,3),(1,4),(1,5),(1,6), ]

[ (2,1),(2,2),(2,3),(2,4),(2,5),(2,6), ]

[ (3,1),(3,2),(3,3),(3,4),(3,5),(3,6), ]

[ (4,1),(4,2),(4,3),(4,4),(4,5),(4,6), ]

[ (5,1),(5,2),(5,3),(5,4),(5,5),(5,6), ]

[ (6,1),(6,2),(6,3),(6,4),(6,5),(6,6) ]

Therefore sample space is equal to 36

n(S) = 36

Let A be the event of getting twin numbers

A={ (1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}

n(A) = 6

P(A) = n(A)/ n(S) = 6/36

${\bf{\orange{1/6}}}$