On adding 1 to the numerator of a fraction it becomes 1/2. Also on adding 1 to the denominator of the original fraction, it becomes 1/3. Find the original fraction
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Answer:
the fraction is -> 2.33.../6
Step-by-step explanation:
lets take the numerator x and denominator y
:. x+1/y=1/2--(1)
x/y+1=1/3--(2)
x=1/3(y+1)
=(y+1)/3--(3)
substitute eq.3 in 1,
[(y+1)/3+1]/y=1/2
:.[(y+1+3)/3]/y=1/2
(y+4)/3=y/2
:.2(y+4)=3y
2y+6=3y
6=3y-2y
6=y--(4)
subt. eq.4 in 3,
x=(6+1)/3
x=7/3
:.x=2.33..
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