On an average rain falls on 12 days in every 30 days find probability that on 3 days of given week
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number of favourable observation by total number of observation is the formula
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Answer:
0.847694
Step-by-step explanation:
Probability that rain falls on a day = p = 12/30 = 2/5
q = 1 - p = 1 - 2/5 = 3/5
n = 7
According to Binomial distribution, P(r)=nCr*q^n-r*p^r
Required probability is P(r=/>3) = 1- P(r=/<2)
Probability that rain will fall on at least 3 days of a given week = 1 - (7C0*(3/5)^7*(2/5)^0 + 7C1*(3/5)^6*(2/5)^1 + 7C2*(3/5)^5*(2/5)^2)
= 1 - (1*2187/78125*1 + 7*729/15625*2/5 + 21*243/3125*4/25)
= 1 - (2187/78125 + 729/15625 + 243/3125)
= 1 - (0.02799+0.046656+0.07766)
= 1-0.152306 = 0.847694
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